用Java生成序列号

Question

I would like to generate sequence number from 01 to 10. But I only want the odd ones. For example,

01 03 05 07 09

I tried this way.

for (int i = 1; i < 10; i++) {
    String sequence = String.format("%02d", i);
    System.out.println(sequence); //this prints out from 01,02,03.... to 09.

So how should I change my code to omit the even ones in between?

Answer 1

Since you want it formatted, only with odd numbers, this outputs:

01 03 05 07 09

for (int i = 1; i < 10; i+=2)
  System.out.println( String.format("%02d", i) );

Answer 2

Use a for loop changing the increment stage:

for (int i = 1; i < 10; i += 2)
    System.out.println(i);

Answer 3

You can just make the loop increment by 2 instead of by just 1!

Example with your code:

for (int i = 1; i < 10; i+=2) 
{
    String sequence = String.format("%02d", i);
    System.out.println(sequence);
}

Answer 4

just use a loop

For loop

for(int i=1;i<=10;i+=2)
System.out.println(i);

While loop

int i=1;
while(i<=10){
System.out.println(i);
i+=2;
}

Do-While loop

int i=1;
do{
System.out.println(i);
i+=2}while(i<=10);