[英]SQL WHERE clause for column of lists
How can I specify a WHERE clause, so that it returns a row if there is an intersection between the column's value (list of strings) and another list of strings provided? 我如何指定WHERE子句,以便在列的值(字符串列表)和提供的另一个字符串列表之间存在交集的情况下返回一行? Something like:
就像是:
SELECT id, names
FROM table
WHERE ANY(names) = ANY(('John', 'Alice', 'Bob'))
So if the value names
column is, eg ['George', 'Bob']
, the row should be returned. 因此,如果值
names
列为例如['George', 'Bob']
,则应返回该行。
You should really use arrays or a table of records for this . 您实际上应该为此使用数组或记录表 。
You can work around your design by splitting strings into arrays at runtime and using PostgreSQL's array features . 您可以通过在运行时将字符串拆分为数组并使用PostgreSQL的数组功能来解决设计问题 。
SELECT id, names
FROM table
WHERE string_to_array(names, ',') && ARRAY['John', 'Alice', 'Bob'];
If your comma separated values have spaces, etc, you might want regexp_split_to_array
instead of string_to_array
. 如果逗号分隔的值包含空格等,则可能需要
regexp_split_to_array
而不是string_to_array
。
If you really can't change your design (which I would recommand, as mentionned by Craig Ringer) 如果您真的无法更改设计(我建议,正如克雷格·林格(Craig Ringer)所述)
You may use regexp_split_to_array 您可以使用regexp_split_to_array
SELECT id, names
from (
SELECT
id,
names,
regexp_split_to_table(names, ', ') as splitted_value
from <yourTable>) t
where splitted_value in ('John', 'Alice', 'Bob')
group by id, names;
or more complicated, with your sample 或更复杂的样品
SELECT id, names
from (
SELECT
id,
names,
regexp_split_to_table(replace(replace(names, '[''', ''), ''']', ''), ''', ''') as splitted_value
from <yourTable>) t
where splitted_value in ('John', 'Alice', 'Bob')
group by id, names;
Another ugly way, using some json functions (as your column datas look like json) 使用某些json函数的另一种丑陋方式(因为您的列数据看起来像json)
"Detail" : I'm not a postgresql expert, and less than all in json datas part. “详细信息” :我不是Postgresql专家,并且少于json数据部分中的所有内容。 So there may be much better way to do this.
因此,可能会有更好的方法来执行此操作。
select id, names
from
(select
id,
names,
replace(cast(json_array_elements(cast(replace(names, '''', '"') as json)) as text), '"', '') as elem
from <yourTable>) t
where elem in ('George', 'Bob');
You can generate your own function which will mimic MYSQL`s FIND_IN_SET 您可以生成自己的函数来模仿MYSQL的FIND_IN_SET
CREATE OR REPLACE FUNCTION find_in_set(str text, strlist text)
RETURNS int AS $$
SELECT i
FROM generate_subscripts(string_to_array($2,','),1) g(i)
WHERE (string_to_array($2, ','))[i] = $1
UNION ALL
SELECT 0
LIMIT 1
$$ LANGUAGE sql STRICT;
http://okbob.blogspot.ro/2009/08/mysql-functions-for-postgresql.html http://okbob.blogspot.ro/2009/08/mysql-functions-for-postgresql.html
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