将数据从CasperJS脚本发送到PHP

Question

I'm trying to get data from CasperJS like this:

Contents of file.php :

$casperjs = "casperjs";
$script = 'add_site.js';
$arg0 = $_POST['new_site'];  
$command = "$casperjs $script $arg0";
$result = shell_exec($command);
echo $result;

Contents of casperjs.js :

casper.then(function() {
  // some code
  utils.dump(JSON.stringify(site));
});
casper.run(function() {
  this.exit();
});

I have nothing on output.

Answer 1

Not 100% on CasperJS, but looking at your PHP code try using json_encode in your script like this:

$casperjs = "casperjs";
$script = 'add_site.js';
$arg0 = $_POST['new_site'];  
$command = "$casperjs $script $arg0";
$result = shell_exec($command);
echo json_encode($result);

Also try setting explicit JSON headers for your output like this:

$casperjs = "casperjs";
$script = 'add_site.js';
$arg0 = $_POST['new_site'];  
$command = "$casperjs $script $arg0";
$result = shell_exec($command);
$json_data = json_encode($result);
header('X-JSON: (' . $json_data . ')');
header('Content-type: application/x-json');
echo $json_data;

Answer 2

I had a problem with casperjs.

PHP must be so:

$casperjs = "/home/k/kreker92/casperjs/bin/casperjs";
$script = 'add_site.js';
$arg0 = $_POST['new_site'];
putenv("PHANTOMJS_EXECUTABLE=/home/k/kreker92/phantomjs/bin/phantomjs");
$command = "$casperjs $script $arg0";
$result = shell_exec($command);
$json_data = json_encode($result);