从内部函数js获取变量值

Question

I am trying to get user current location and pass those latitude/longitude coordinates to a map. The map will be used as a website background image.

I was partially successful with this code:

  navigator.geolocation.getCurrentPosition(showPosition);

    function showPosition(position) {
        xss =position.coords.latitude + 
        "," + position.coords.longitude; 


  }
var position = [32.5590985,35.8415147];

Now I want the value of xss to be inside this variable:

var position = [32.5590985,35.8415147];

basically I was trying to get the values from the function but without success.

How should I go about getting a value from inside the function?

HTML

<div id="googlemaps"></div>

JS Code

    navigator.geolocation.getCurrentPosition(showPosition);

    function showPosition(position) {
        xss =position.coords.latitude + 
        "," + position.coords.longitude; 


  }
var position = [32.5590985,35.8415147];

function initialize() {

    var myOptions = {
        zoom: 17,
        streetViewControl: false,
        scaleControl: false,
        mapTypeId: google.maps.MapTypeId.ROADMAP
    };

    map = new google.maps.Map(document.getElementById('googlemaps'),
        myOptions);


    latLng = new google.maps.LatLng(position[0], position[1]);

    map.setCenter(latLng);

    marker = new google.maps.Marker({
        position: latLng,
        map: map,
        draggable: false,
        animation: google.maps.Animation.DROP
    });


}
google.maps.event.addDomListener(window, 'load', initialize);

Answer 1

How about you set the value of position variable from inside the showPosition function?

var position;

navigator.geolocation.getCurrentPosition(showPosition);

function showPosition(pos) {
  position = [pos.coords.latitude, pos.coords.longitude];
}

Answer 2

Assuming navigator.geolocation.getCurrentPosition is asynchronous, this looks like a classic "Get results from an asynchronous request" problem. Please see https://stackoverflow.com/a/14220323/380487 for a detailed answer.