Oracle SQL Developer查询从同一列返回2个值的计数

Question

I am trying to count the number of two types of transactions in a column and to return a value of 0 if there are none. The table is Transaction, the columns I want returned are the account number and a column for the count each of the two transactions listed. here's what I have, but it doesn't run:

SELECT 
ACCTNBR, 
COUNT(CASE when RTXNTYPCD='XDEP'then 1 else 0) AS Deposits,
COUNT(CASE when RTXNTYPCD='PWTH'then 1 else 0) AS Debits

FROM  
TRANSACTION 

WHERE 
((POSTDATE BETWEEN TO_DATE('05-01-2014','MM-DD-YYYY')) AND TO_DATE('05-31-2014','MM-DD-YYYY')) 

and ACCTNBR in ( 406,   1206,   1347,   4556,   6668,   9845)

GROUP BY 
ACCTNBR 

Answer 1

The count function counts any value that isn't null . Since both 0 and 1 are not null , both your count s will return the total number of rows in your table. Instead, you should use sum :

SELECT 
 ACCTNBR, 
 SUM(CASE when RTXNTYPCD='XDEP' then 1 else 0 END) AS Deposits,
 SUM(CASE when RTXNTYPCD='PWTH' then 1 else 0 END) AS Debits
FROM  
 TRANSACTION 
WHERE 
 ((POSTDATE BETWEEN TO_DATE('05-01-2014','MM-DD-YYYY')) AND 
                     TO_DATE('05-31-2014','MM-DD-YYYY')) 
   and ACCTNBR in ( 406,   1206,   1347,   4556,   6668,   9845)
GROUP BY 
 ACCTNBR