bash-用sed替换字符串

Question

For some mysterious reason, some elements in my CSV data appear as s/stWgvN52??f2& ?" s/stWgvN52??f2& ?" instead of stWgvN522tw0JtZZnyXj , which messes up the file because I have ; set as the CSV delimiter.

I attempted to replace the defective string using sed as follows:

$ sed -i 's/stWgvN52??f2& ?"/stWgvN522tw0JtZZnyXj/g' file.csv

but I get the following error: sed: 1: "access_logs_2014-04.csv": command a expects \\ followed by text

What is the reason?

Answer 1

When you use the -i option, you have to specify the extension of the backup file that gets made. Some versions of sed expect the extension directly appended to the -i option, so what you wrote would work. But other versions (like the version on OS X) require it to be a separate option, so you have to write:

sed -i '' 's/stWgvN52??f2& ?"/stWgvN522tw0JtZZnyXj/g' file.csv

to specify that you don't want a backup file.