如何返回与Neo4j具有多个关系的节点？

Question

I want to return a list of 'Group' nodes which have more than one 'Thing' node belonging to each of them. There are some duplicate relationships, so I'm counting DISTINCT Things. This query seems to work fine so far:

MATCH (n:Thing)-[r:BELONGS_TO]-(g:Group)
WITH g, count(DISTINCT n) as thing_cnt
WHERE thing_cnt > 1
RETURN g, thing_cnt ORDER BY thing_cnt

I'd like to be able to visualise all of these Group nodes and the Things that belong to them, so I tried this:

MATCH (n:Thing)-[r:BELONGS_TO]-(g:Group)
WITH g, count(DISTINCT n) as thing_cnt
WHERE thing_cnt > 1
RETURN n, g

But I get an error telling me that n is not defined. Can anyone suggest a way to do this? Thanks!

Answer 1

The WITH clause needs to include n :

MATCH (n:Thing)-[r:BELONGS_TO]-(g:Group)
WITH n, g, count(DISTINCT n) as thing_cnt
WHERE thing_cnt > 1
RETURN n, g

As an aside, you should always specify the directionality of your relationships, if possible. For example, (n:Thing)-[r:BELONGS_TO]->(g:Group) . At the very least, that improves the readability and hum-understandability of your graph model. Also, it could speed up you query as well.