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count元素使用Xquery并返回值

[英]count element using Xquery and return the value

my xml data: 我的xml数据:

<a>
   <book>
        <pub>John</pub>
   </book>
   <book>
        <pub>John</pub>
    </book>
    <book>
         <pub>Mary</pub>
    </book>
</a>

So i want to count number for each and display them 所以我想计算每个的数字并显示它们

Expected output: 预期产量:

 <result>
         <pub>John</pub>
         <total>2</total>
 </result>
 <result>
         <pub>Mary</pub>
         <total>1</total>
  </result>

But my output: 但我的输出:

 <result>
         <pub>John</pub>
         <total>1</total>
 </result>
<result>
         <pub>John</pub>
         <total>1</total>
 </result>
 <result>
         <pub>Mary</pub>
         <total>1</total>
  </result>

code i using : 代码我使用:

for $b in /a/book
let $count := count($b/pub)
for $pub in $b/pub
return
     <result> {$pub} <total>{$count}</total></result>

it keep looping the same data but not group it . 它不断循环相同的数据,但不对其进行分组。 even i use distinct-values it's still same. 即使我使用不同的值,它仍然是相同的。 what error in my code? 我的代码中有什么错误?

If using an XQuery 3.0 capable XQuery processor, you can also take advantage of the group by flwor statement: 如果使用支持XQuery 3.0的XQuery处理器,您还可以group by flwor语句利用该group by

for $book in /a/book
let $publisher := $book/pub
group by $publisher
return
  <result>
    <pub>{ $publisher }</pub>
    <count>{ count($book) }</count>
   </result>

Grouping works using distinct-values . 分组使用distinct-values You can count all the book s or pub s and filter only the ones that match the current iteration. 您可以计算所有bookpub并仅过滤与当前迭代匹配的book

This: 这个:

let $b := /a/book/pub
  for $pub in distinct-values($b)
      let $count := count($b[. eq $pub])
      return <result>
                <pub>{$pub}</pub> 
                <total>{$count}</total>
             </result>

will produce: 将产生:

<result>
   <pub>John</pub>
   <total>2</total>
</result>
<result>
   <pub>Mary</pub>
   <total>1</total>
</result>

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