PHP MySQL（插入查询）

Question

I have simple payment form and it is include voucher_id , customer_id , amount , payment_type , transaction_type and date .

Transaction_type's are withdrawls and deposits.

My data base table should not contain "amount" column. it has credit and debit column. In this case, I want to INSERT amount to debit column if transaction type ="Withdraws" of INSERT amount to credit column if Transaction_type ="Deposits" .

When I INSERT data to table show:

Column count doesn't match value count at row 1

Because, table has debit and credit column. But my form has one column and it is name is amount. How can INSERT this query to sort out my question.

<?php

// save data if form is submitted
    if(isset($_POST['submitted'])){

        // catch data
        $voucher_numebr = $_POST['voucher_numebr'];
        $member_id = $_POST['member_id'];
        $amount = $_POST['amount'];
        $acc_type = $_POST['acc_type'];
        $payment_type = $_POST['payment_type'];
        $discription = $_POST['discription'];
        $created = date("Y-m-d H:i:s");

        // $balance = $_POST['balance'];

        $tranaction_type = $_POST['tranaction_type'];
        $balance="NOT DEFINE";

            //insert  to the tbl_customer_account


            if($tranaction_type == "Withdrawls."){
                //echo "1";
                $sql ='INSERT INTO tbl_customer_account VALUES(NULL,"'.$voucher_numebr.'","'.$member_id.'","'.$amount.'","'.$acc_type.'","'.$payment_type.'","'.$discription.'","'.$created.'","'.$tranaction_type.'","'.$balance.'")';

            }
            else{
                $sql ='INSERT INTO tbl_customer_account VALUES(NULL,"'.$voucher_numebr.'","'.$member_id.'","'.$amount.'","'.$acc_type.'","'.$payment_type.'","'.$discription.'","'.$created.'")';

            }

        //else{




        //}


        mysql_query($sql, $conn) or die(mysql_error());
        echo 'form submitted'; 
        echo '<br />';
        echo mysql_affected_rows(); die();

    }



?>

Answer 1

Column count doesn't match value count at row ... means you have specified a different amount of columns than you have for values.

-- correct
INSERT INTO table (col1, col2) VALUES ('val1', 'val2');

-- error: 1 column, 2 values
INSERT INTO table (col1) VALUES ('val1', 'val2'); 

-- error: 2 columns, 1 value
INSERT INTO table (col1, col2) VALUES ('val1'); 

Check your query and fix it so the number of columns and values match.

Answer 2

Since you're not specifying a value for each column, you have to specify which columns you're updating. This is a good practice even when you are updating all columns, so you don't have to worry about future changes to the table's structure (eg, adding or moving columns).

You haven't included the table structure, so I'll have to guess your column names:

        if($tranaction_type == "Withdrawls."){
            //echo "1";
            $sql ='INSERT INTO tbl_customer_account (some_field, voucher_number, member_id, debits, account_type, payment_type, description, created, transaction_type, balance) VALUES(NULL,"'.$voucher_numebr.'","'.$member_id.'","'.$amount.'","'.$acc_type.'","'.$payment_type.'","'.$discription.'","'.$created.'","'.$tranaction_type.'","'.$balance.'")';

        }
        else{
            $sql ='INSERT INTO tbl_customer_account (some_field, voucher_number, member_id, credits, account_type, payment_type, description, created) VALUES(NULL,"'.$voucher_numebr.'","'.$member_id.'","'.$amount.'","'.$acc_type.'","'.$payment_type.'","'.$discription.'","'.$created.'")';

        }

I suppose there's a reason you're leaving out transaction_type and balance for deposits?