两个通用接口相互需求，如何正确实现它们？

Question

I want to use 2 Implementations, but I'm not sure how I should pass each Implementation to each of them. This is what I've got so far:

Interface of A:

public interface A<T extends A<T, U>, U extends B<T, U>>{
}

Interface of B:

public interface B<T extends A<T, U>, U extends B<T, U>> {
}

Implementation of A:

public class AImpl<T extends B<AImpl<T>, T>> implements A<AImpl<T>, T>{
}

Implementation of B:

public class BImpl<T extends A<T, BImpl<T>>> implements B<T, BImpl<T>> {
}

Now i want to use A and B. I'm not really sure how to implement them. Here is my initial attempt:

Main:

//this doesn't work
private AImpl<BImpl> a; 
private BImpl<AImpl> b; 

public main() {
    a = new AImpl<BImpl>();
    b = new BImpl<AImpl>();
}

Answer 1

Inheritance can be far less useful for an interface than a class.

SUGGESTION: Just refactor and simplify your interfaces so you don't have to extend anything but the class itself!

Fewer, smaller interfaces; and shallow inheritance hierarchies for interfaces, are generally a Good Thing. IMHO...