RestSharp：将Xml反序列化为c＃对象返回null

Question

i've an xml from some api :

<auditypes>
     <auditype code="a" description="aaa"/>
     <auditype code="b" description="bbb"/>
     <auditype code="c" description="ccc"/>
     <auditype code="d" description="ddd"/>
     <auditype code="e" description="eee"/>
</auditypes>

and mapping as object in C# class :

    public class auditypes
    {
        public List<auditype> auditype { get; set; }
    }

    public class auditype
    {
        public string code { get; set; }
        public string description { get; set; }
    }

I call it with this function :

    public List<auditypes> Execute<auditypes>(RestRequest request) where auditypes : new()
    {
        var client = new RestClient();
        client.BaseUrl = "https://www.myurl.com/auditypes";
        var response = client.Execute<auditypes>(request);

        return response.Data as List<auditypes>;
    }

    public List<auditypes> GetCall()
    {
        var request = new RestRequest();
        request.RequestFormat = DataFormat.Xml;
        request.RootElement = "auditype";
        return Execute<auditypes>(request);
    }

but it always return null, does anyone knows why is this happening?

Answer 1

The generic parameter passed to Execute<T> is the type that should be deserialized by the RestSharp library. That means that your response.Data property is already of type T , which in your case is auditypes . But when you return you try to cast it to a List<auditypes> where no such cast exists.

Also, there is no need for the type constraint, as your method is not generic as it accepts an explicit type.

Refactor your method:

public auditypes Execute<auditypes>(RestRequest request)
{
    var client = new RestClient();
    client.BaseUrl = "https://www.myurl.com/auditypes";
    var response = client.Execute<auditypes>(request);

    return response.Data;
}

Answer 2

Finally, it work for me :)

public auditypes Execute<auditypes>(RestRequest request) where auditypes : new()
{
    var client = new RestClient();
    client.BaseUrl = "https://www.myurl.com/auditypes";
    var response = client.Execute<auditypes>(request).Data;

    return response;
}

public auditypes GetCall()
{
    var request = new RestRequest();
    request.RequestFormat = DataFormat.Xml;
    return Execute<auditypes>(request);
}