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RegExp 未捕获 TypeError:无法读取 null 的属性“1”

[英]RegExp uncaught TypeError: Cannot read property '1' of null

I found this code;我找到了这个代码;

navigator.appVersion.match(/MSIE ([\\d.]+)/)[1];

For detecting browser version.用于检测浏览器版本。 This code works in IE 8 below but not on google chrome.此代码适用于下面的 IE 8,但不适用于谷歌浏览器。 The error in google chrome says;谷歌浏览器中的错误说;

Uncaught TypeError: Cannot read property '1' of null

and it points to the line where this code belongs;它指向此代码所属的行;

navigator.appVersion.match(/MSIE ([\\d.]+)/)[1];

Any idea how to fix this issue?知道如何解决这个问题吗?


just to make things clear what i'm trying to accomplish here is to detect the browser version:只是为了弄清楚我在这里要完成的是检测浏览器版本:

var version = navigator.appVersion.match(/MSIE ([\d.]+)/)[1];

if(version <= 8.0)

{
   execute code;
}

Everything works fine in IE but I got an error in google chrome which is:在 IE 中一切正常,但在 google chrome 中出现错误,即:

Uncaught TypeError: Cannot read property '1' of null未捕获的类型错误:无法读取 null 的属性“1”

and it points to the line where this code belongs;它指向此代码所属的行;

navigator.appVersion.match(/MSIE ([\\d.]+)/)[1]; navigator.appVersion.match(/MSIE ([\\d.]+)/)[1];

match can return null if regexp don't find anything.如果 regexp 没有找到任何东西, match 可以返回null So you must first get matches and check have you any match or not.因此,您必须首先获得匹配项并检查您是否匹配。 Try this:尝试这个:

var ieMatches = navigator.appVersion.match(/MSIE ([\d.]+)/);
var isIE = !!ieMatches[1];

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