sed / awk在正则表达式中指定范围

Question

I have a file list output like this:

/path/F201405151800
/path/F201405151900
/path/F201405152000
/path/F201405152100

I piped this output to sed and used the following syntax:

sed -n '/F.\{8\}'$var1'/,/F.\{8\}'$var2'/p'

$var1 and $var2 are user inputs and as it can be seen, they refer to hours of the day in my files list. The above syntax works perfectly if $var1 and $var2 values are found. But if the value of $var1 is 16, and $var2 is 19 sed will not output anything because 16 will not be found in the above file list range.

A solution to this was:

sed -n '/F.\{8\}1[6-9]/p'

...which works but the issue I am facing now is how to specify double digit ranges in order to include something like: 16-20. I tried globbing between single quotes (like I'm doing with variables) like this:

sed -n '/F.\{8\}'{16..21}'/p'

...but the output I get is:

sed: can't read /F.\{8\}16/p: No such file or directory
sed: can't read /F.\{8\}17/p: No such file or directory
sed: can't read /F.\{8\}18/p: No such file or directory
sed: can't read /F.\{8\}19/p: No such file or directory
sed: can't read /F.\{8\}20/p: No such file or directory
sed: can't read /F.\{8\}21/p: No such file or directory

I don't really need to use sed, I explored some options with awk but could not obtain what I want, the main issue being that I can't figure out how to specify a regex RS so that I have the hours block as an awk field and do some conditions like

'$2 > 16 && $2 < 21 {print}'

Answer 1

Try to add -e :

sed -n -e '/F.\{8\}'"$var1"'/,/F.\{8\}'"$var2"'/p'

And always quote the variables to prevent word splitting.

Update:

awk -v A=17 -v B=21 -F/ '!/\/F[0-9]{12}$/{next} {h = substr($NF, 10, 2)} h >= A && h <= B'

Answer 2

You can use this awk:

awk -F'/' '{h=$3; gsub(/^F[0-9]{6}|[0-9]{4}$/, "", h)} h > 12 && h < 21' file
/path/F201405151800
/path/F201405151900
/path/F201405152000
/path/F201405152100

Answer 3

为了获得两位数的范围，您可以尝试执行以下操作：

sed -n '/F.\{8\}(1[6-9]|2[01])/p'