总结查询mongodb php

Question

I have this collection

> db.test.find()
{ "_id" : ObjectId("5398ddf40371cdb3aebca3a2"), "name" : "ahmed", "qte" : 30 }
{ "_id" : ObjectId("5398de040371cdb3aebca3a3"), "name" : "demha", "qte" : 35 }
{ "_id" : ObjectId("5398de140371cdb3aebca3a4"), "name" : "ahmed", "qte" : 50 }
{ "_id" : ObjectId("5398de210371cdb3aebca3a5"), "name" : "ahmed", "qte" : 60 }

i would like to sum "qte" where "name"= "ahmed" and print the sum with php i know how to do with SQL but i have no idea how it is in mongodb.

Thanks :)

Answer 1

Use the aggregation framework.

Assuming you have an the current collection as $collection

result = $collection->aggregate(array(
    array(
        '$match' => array(
            'name' => 'ahmed'
        )
    ),
    array(
        '$group' => array(
            '_id' => NULL,
            'total' => array(
                '$sum' => '$qte'
            )
        )
    )
));

The two parts are the $match to meet the criteria, and the $group to arrive at the "total" using $sum

See other Aggregation Framework Operators and the Aggregation to SQL Mapping chart for more examples.

Answer 2

This is done with an aggregate statement:

db.test.aggregate([
    {
        $match: {
            name: "ahmed"
        } 
    },
    {
        $group: {
            _id:"$name",
            total: {
                $sum: "$qte" 
            }
        }
    }
])