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web.xml根元素后面的文档中的标记必须格式正确

[英]web.xml the markup in the document following the root element must be well-formed

I'm trying to set up DWR, direct web remoting, and they had me put in the web.xml this piece of code here, 我正在尝试设置DWR,直接进行Web远程处理,他们让我在这里将这段代码放在web.xml中,

<servlet>
  <display-name>DWR Servlet</display-name>
  <servlet-name>dwr-invoker</servlet-name>  
  <servlet-class>org.directwebremoting.servlet.DwrServlet</servlet-class>
  <init-param>
     <param-name>debug</param-name>
     <param-value>true</param-value>
  </init-param>
</servlet>

<servlet-mapping>
  <servlet-name>dwr-invoker</servlet-name>
  <url-pattern>/dwr/*</url-pattern>
</servlet-mapping>

but I get the error the markup in the document following the root element must be well-formed, and it is at the servlet-mapping part. 但是我得到一个错误,即根元素后面的文档中的标记必须格式正确,并且位于servlet映射部分。 I tried putting the servlet mapping inside of servlet and it got rid of the error but the webpage http://localhost:8081/WebProject01/dwr/ still wouldn't come up. 我尝试将servlet映射放入servlet并摆脱了错误,但是网页http://localhost:8081/WebProject01/dwr/仍然无法显示。 The dwr.xml didn't have any errors so that looked good. dwr.xml没有任何错误,所以看起来不错。 Is there another way to fix the error message? 还有另一种方法可以修复错误消息? Thanks for your time. 谢谢你的时间。

<?xml version="1.0" encoding="UTF-8"?>
<servlet>
    <display-name>DWR Servlet</display-name>
    <servlet-name>dwr-invoker</servlet-name>
    <servlet-class>org.directwebremoting.servlet.DwrServlet</servlet-class>
    <init-param>
        <param-name>debug</param-name>
        <param-value>true</param-value>
    </init-param>
</servlet>
<servlet-mapping>
    <servlet-name>dwr-invoker</servlet-name>
    <url-pattern>/dwr/*</url-pattern>
</servlet-mapping>

is not a valid web.xml (this is not even valid XML) 不是有效的web.xml (甚至不是有效的XML)

The root element of a web.xml is web-app . web.xml的根元素是web-app Please refer to the documentation to understand how a web deployment descriptor should look like and what it is for. 请参考文档以了解Web部署描述符的外观以及其用途。

You could edit you web xml in this way: 您可以通过以下方式编辑Web xml:

<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
    http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" 
    id="WebApp_ID" version="3.0">
    <servlet>
        <display-name>DWR Servlet</display-name>
        <servlet-name>dwr-invoker</servlet-name>  
        <servlet-class>org.directwebremoting.servlet.DwrServlet</servlet-class>
        <init-param>
            <param-name>debug</param-name>
            <param-value>true</param-value>
        </init-param>
    </servlet>

    <servlet-mapping>
        <servlet-name>dwr-invoker</servlet-name>
        <url-pattern>/dwr/*</url-pattern>
    </servlet-mapping>
</web-app>

version="3.0" must be support supported by your application server (for example tomcat 7.x) Otherwise pleas look for the corresponding declarations for the servlet spec your app-server implements, for example for 2.5 您的应用程序服务器必须支持version="3.0" (例如tomcat 7.x),否则请为您的应用程序服务器实现的servlet规范查找相应的声明, 例如2.5

<web-app xmlns="http://java.sun.com/xml/ns/j2ee" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
    http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    version="2.5">

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