PHP如果有图像显示图像，否则为文本

Question

I'm a front-end web developer struggling with some theme option support. I am struggling to write a simple function in my header.php which allows me to do the following:

"if user uploads an image, use the image. If else use 'logo_text' and echo output. If user doesnt upload image or logo_text use default of 'My Site'"

Can anyone point me in the right direction to get started? I don't know where to begin for this one.

    <li class="name">
      <!-- Logo Text -->
      <h1><a href="<?php bloginfo('url'); ?>/home" title="<? echo esc_attr( get_bloginfo( 'name', 'display' ) ); ?>" rel="home">
        <? $novus_logo_text = get_option('novus_logo_text'); echo $novus_logo_text; ?>
      </a></h1>
      <!-- Logo Image -->
      <a href="<?php bloginfo('url'); ?>/home" title="<? echo esc_attr( get_bloginfo( 'name', 'display' ) ); ?>" rel="home">
        <? $novus_logo_upload = get_option('novus_logo_upload'); echo '<img class=\"logo"\ src="'.$novus_logo_upload.'" width=\"100%"\ />'; ?>
      </a>
    </li>

The code above works just fine. However if a client uses both the logo_text input and uploads a logo image they will both output. I need either or, with the image taking priority. I hope this makes sense.

Answer 1

You should really learn basic control structures even if your a front end guy, if , while , for , foreach , switch .

<li class="name">
  <?php if($novus_logo_upload = get_option('novus_logo_upload')){ ?>
  <!-- Logo Image -->
  <a href="<?php bloginfo('url'); ?>/home" title="<? echo esc_attr( get_bloginfo( 'name', 'display' ) ); ?>" rel="home">
    <? echo '<img class=\"logo"\ src="'.$novus_logo_upload.'" width=\"100%"\ />'; ?>
  </a>
  <?php } else if($novus_logo_text = get_option('novus_logo_text')){ ?>
  <!-- Logo Text -->
  <h1><a href="<?php bloginfo('url'); ?>/home" title="<? echo esc_attr( get_bloginfo( 'name', 'display' ) ); ?>" rel="home">
    <? echo $novus_logo_text; ?>
  </a></h1>
  <?php } else { ?>
  <!-- Default -->
  <?php } ?>
</li>