[英]Async-WaterFall not working as expected
waterfall function with two calls but the second on is not waiting for the first one to completely finish. 带有两个调用的瀑布函数,但是第二个调用不等待第一个完全完成。 The first one has a mongodb.find() call in it. 第一个调用了mongodb.find()。 Here is the async-waterfall function 这是异步瀑布功能
app.get("/news", function(req, res) {
async.waterfall([
function (callback) {
var blogs = tendigiEngine.getAllBlogs(callback);
callback(null, blogs);
},
function (blogs, callback) {
var array = tendigiEngine.seperateBlogs(blogs, callback);
callback(null, array );
}
], function (err, result) {
// result now equals 'done'
console.log("done");
console.log(result);
});
});
Here are the two functions being called: getAllBlogs(): 这是被调用的两个函数:getAllBlogs():
exports.getAllBlogs = function() {
Blog.find(function(err, theBlogs){
if(!err) {
return theBlogs;
}
else {
throw err;
}
});
}
seperateBlogs(): seperateBlogs():
exports.seperateBlogs = function(blogs) {
if(blogs.length === 0 ) {
return 0;
}
else {
blogs.reverse();
var blog = blogs[0];
blogs.shift();
var finArray = [blog, blogs];
return finArray;
}
console.log("asdf");
}
It is important that seperateBlogs won't be called before getAllBlogs() has returned theBlogs, but it is being called before the value is returned. 重要的是,在getAllBlogs()返回theBlogs之前不会调用seperateBlogs,但是在返回值之前将调用它。 I used Async_Waterfall to avoid this problem but it keeps recurring, which means I am using it wrong. 我使用Async_Waterfall来避免此问题,但它会不断发生,这意味着我使用错误。 What am I doing wrong here and how can I fix it? 我在这里做错什么,如何解决?
Thanks! 谢谢!
Your exported functions are missing the callback parameters: 您导出的函数缺少回调参数:
exports.getAllBlogs = function(cb) {
Blog.find(cb);
};
exports.seperateBlogs = function(blogs, cb) {
if (blogs.length === 0 )
return cb(null, blogs);
blogs.reverse();
var blog = blogs[0];
blogs.shift();
cb(null, [blog, blogs]);
}
Then your main code can be simplified as well: 然后,您的主要代码也可以简化:
async.waterfall([
tendigiEngine.getAllBlogs,
tendigiEngine.seperateBlogs
], function (err, result) {
// result now equals 'done'
console.log("done");
console.log(result);
});
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