正则表达式，用于以两个特殊字符开头的字符串

Question

I want to write a regular expression to force the user to fill an input with a 10 digit character that should start with 09. Like the followings:

0912345678
0968765432
.
.
.

I wrote th following to check the length:

[StringLength(10)]
[MinLength(10)]

Now I dont know how to check that its started with 09.

Thanks for any idea.

Answer 1

Try this regex:

^09\d{8}$

Explanation:

• ^ - Beginning of the string
• 09 - Matches the digits 09 literally
• \\d{8} - Matches exactly 8 digits
• $ - End of the string

Live demo