在PHP中构建多维数组

Question

I have got couple of arrays.

Array 1

Array
(
    [0] => 501
    [1] => 502
    [2] => 503
    [3] => 505
)

Array 2

Array
(
    [0] => Array
        (
            [0] => 503
            [1] => 1
        )

    [1] => Array
        (
            [0] => 505
            [1] => 1
        )

)

Now my desired array structure should be

Array
    (
        [0] => Array
            (
                [0] => 503
                [1] => 1
            )

        [1] => Array
            (
                [0] => 505
                [1] => 1
            )
        [2] => Array
            (
                [0] => 501
                [1] => 0
            )
        [3] => Array
            (
                [0] => 502
                [1] => 0
            )

    ) 

My code is

foreach($array1 as $k => $v)
{
    if( $array2[$k][0] == $v)
    {
        $finalArr[] = array($array2[$k][0],$array2[$k][1]);
    }
    else
    {
        $finalArr[] = array($v,0);
    }


}

Now it's giving me the right array structure which I want but the value is missing for the elements which are present in both array.

Answer 1

The issue is with this line:

if( $array2[$k][0] == $v)

$k is referring to the index of $array1, not $array2... so unless the elements in both arrays are perfectly in sync, your script will not work.

Answer 2

Try this:

$a_vals2 = array_map(
    function ($v) { return $v[1]; },
    $array2
);
$result = $array1;
foreach (array_diff($array1, $a_vals2) as $v) {
    $result[] = array($v, 0);
}

Answer 3

if( $array2[$k][0] == $v) will never return true (for provided arrays) because you're checking the indexes of the arrays together. For example, 503 == 501 and 505 == 502 on the second index. Seems to me like your code will just make a copy of the first array (in this example).