php -f file.php cats文件到命令行？

Question

I've just written a simple php file only containing:

echo 'some text';

I now want to execute that from the command line. When I do php -v , I get:

HP 5.5.12-1~dotdeb.1 (cli) (built: May  6 2014 03:56:10)
Copyright (c) 1997-2014 The PHP Group
Zend Engine v2.5.0, Copyright (c) 1998-2014 Zend Technologies
    with Zend OPcache v7.0.4-dev, Copyright (c) 1999-2014, by Zend Technologies
    with Xdebug v2.2.5, Copyright (c) 2002-2014, by Derick Rethans

but when I do php -f file.php , it simply cats the file:

# php -f file.php
echo 'some text';
#

I also tried php file.php , but to no avail.

Does anybody know what I'm doing wrong here? All tips are welcome!

Answer 1

Juste将开始和结束标记<?php ... ?>到file.php中，它将起作用。