[英]SQL Query Produce all Combinations
I have searched and looked but can't quite get the SQL query to work as I need. 我已经搜索并查看了,但是无法完全按照我的需要运行SQL查询。 I have this data:
我有此数据:
10019201 GEE78316634770
10019201 SIE78308706478
10019202 GEE78316634773
10019202 SIE78308706477
10019202 SIE78308706499
10019202 SIE78308706900
10019501 SIE78308706917
10019501 GEE78316634930
I want to create the following output based on the fact that the first column match, the following output: 我想基于第一列匹配的事实创建以下输出,以下输出:
GEE78316634770 SIE78308706478
SIE78308706478 GEE78316634770
GEE78316634773 SIE78308706477
GEE78316634773 SIE78308706499
GEE78316634773 SIE78308706900
SIE78308706477 GEE78316634773
SIE78308706477 SIE78308706499
SIE78308706477 SIE78308706900
SIE78308706499 GEE78316634773
SIE78308706499 SIE78308706477
SIE78308706499 SIE78308706900
SIE78308706900 GEE78316634773
SIE78308706900 SIE78308706477
SIE78308706900 SIE78308706499
SIE78308706917 GEE78316634930
GEE78316634930 SIE78308706917
So the first two records with 10019201 are matched up in the results as 因此,结果为10019201的前两个记录将匹配为
GEE78316634770 SIE78308706478
SIE78308706478 GEE78316634770
the next set of records with 10019202 - there are four matches so the results are: 下一组记录为10019202的记录-有四个匹配项,因此结果为:
GEE78316634773 SIE78308706477
GEE78316634773 SIE78308706499
GEE78316634773 SIE78308706900
SIE78308706477 GEE78316634773
SIE78308706477 SIE78308706499
SIE78308706477 SIE78308706900
SIE78308706499 GEE78316634773
SIE78308706499 SIE78308706477
SIE78308706499 SIE78308706900
SIE78308706900 GEE78316634773
SIE78308706900 SIE78308706477
SIE78308706900 SIE78308706499
each one matched with the other 3. 彼此匹配3。
Can someone help me with the query to get the results I need? 有人可以帮助我查询以获得所需的结果吗?
Thanks! 谢谢! Leslie
莱斯利
Use a self-join: 使用自联接:
{using column names ID
and Value
just to show syntax} {使用列名
ID
和Value
只是为了显示语法}
SELECT
t1.Value Value1,
t2.Value Value2
FROM table t1
INNER JOIN table t2
ON t1.ID = t2.ID
AND t1.Value <> t2.Value
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