指定主类 Spring-Boot 命令行

Question

I use maven plugin to set the main class like this :

<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
<configuration>
    <mainClass>com.myapp.main.MainClass</mainClass>
</configuration>
</plugin>

But sometimes I want run my app with another main class. What is the command line arguments to do this?

java -jar myapp-1.0.jar ...

Thx

Answer 1

以下命令可以解决问题：

java -cp my-app.jar -Dloader.main=myApplicationClass org.springframework.boot.loader.PropertiesLauncher

Answer 2

There's a launcher for that in Spring Boot already . You need to build the jar with that as the Main-Class ( by setting the layout in the build config ).

Answer 3

Executing from Windows PowerShell I needed this format (with the quotes):

java -cp .\\myjarfile.jar -D"loader.main=com.app.etc.FullyQualifiedMainClass" org.springframework.boot.loader.PropertiesLauncher

To clarify the accepted answer: You can directly modify the loader.main property in the jar's META-INF/MANIFEST.MF file, if you're ok with a more static solution.

Answer 4

对于 WAR 文件：

java -cp salamander-1.0.0.war -Dloader.path=WEB-INF/classes,WEB-INF/lib -Dloader.main=com.frog.katak.MyMainClass org.springframework.boot.loader.PropertiesLauncher