在cd之后获取正在运行的文件的路径到python中的另一个目录

Question

I have following simple script test.py in directory /Users/apps :-

import os
os.chdir("/Users/apps/update/diiferent_path")
path = os.path.dirname(os.path.abspath(__file__))
print(path)

I am getting path value as /Users/apps/update/diiferent_path because I have changed the directory. How can I get test.py path ie /Users/apps after changing directory.

Answer 1

It's impossible to do it after the chdir (unless, of course, if __file__ already contains the absolute path), because the information is lost. There is no such thing as what was the current directory when the process started stored anywhere automatically. But you can store it manually by calling os.path.abspath(__file__) before calling the chdir .

Answer 2

I agree with pts post that storing the path is the way to go. It best shows your intention of getting the original path, despite what modifications are done throughout the script.

For reference sake two workarounds. The path changes because the script is executed by name. The interpreter then finds the file in the current directory. The current directory changes, and thus the absolute path of both __file__ and sys.argv .

One way around that is to call the script with an absolute path . Another is to realize that the path of the script is automatically added to the PYTHONPATH , ie to sys.path . The following script illustrates that:

#!/usr/bin/python

import os
import sys

os.chdir("/usr/bin")
print(os.path.abspath(__file__))
print(os.path.abspath(sys.argv[0]))
print(sys.path[0])

The output:

# /tmp$ ./so24323731.py 
/usr/bin/so24323731.py
/usr/bin/so24323731.py
/tmp
# /tmp$ /tmp/so24323731.py 
/tmp/so24323731.py
/tmp/so24323731.py
/tmp