Perl-正则表达式转义失败

Question

Following Perl onliner fails, the regex is ok, though. Something is wrong with the esacping, but I can't finger out what. Can someone help me out? I'm on Linux/Bash.

perl -pi -e '(?<=\.zip).*?(hren)|(^\")|(^\r\n|^\n)|(^New).*?(\")|(\,\s)' file

This is the error message:

Unmatched ) in regex; marked by <-- HERE in m/<=\.zip) <-- HERE .*/ at -e line 1.

Answer 1

As @mpapec pointed out, you forgot to add m// to make the statement into a regex. So why do you get a regex error if it isn't being treated as a regex?

Perl thinks you're trying to use the ?PATTERN? format for pattern matching, see perlop . It looks at:

?<=\.zip).*?

Attempts to interpret the bit between ?..? as a regex and correctly identifies the unmatched ) .