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分页显示分页显示问题

[英]Pagination display issue with number pages

hey guys my English is not very good 'but i try to explain my self clear. 嘿,我的英语不是很好'但是我尝试解释清楚自己的意思。 i'm creating pagination and all of my code is working perfect. 我正在创建分页,并且我所有的代码都运行良好。

The problem is, that i want to display only five numbers of pages and on click on next button i hide one and showing new one. 问题是,我只想显示五个页面,然后单击下一步按钮就隐藏了一个页面并显示了新页面。 it's looks like that. 看起来像那样。

next 12345 prev

next 23456 prev

Thank's for advice guys. 谢谢大家的建议。

Here is my code : 这是我的代码:

 <?php

  $dbh = new PDO("mysql:host=localhost;dbname=northwind", "root", "123");


  $query = $dbh->prepare("SELECT ContactName FROM Customers");
  $query->execute();
  $numRows = $query->rowCount();


  if (isset($_GET['pn'])) {
      $pn = $_GET['pn'];
  } else {
      $pn = 1;
  }

  $startPage = 1;
  $perPage = 9;


  $lastPage = ceil($numRows / $perPage);


  if ($pn < 1) {
     $pn = 1;
  } else if ($pn > $lastPage) {
     $pn = $lastPage;
  }

  $controls = '';


   if ($pn != $lastPage) {

        $controls .= '<a id="next" href="' . $_SERVER['PHP_SELF'] . '?pn=' . ($pn + 1) . '"> next </a>';
   }


    for ($i=1; $i <= $lastPage; $i++) {

         if ($i == $pn) {
              $background = ' red;';
         } else {
              $background = ' green;';
         }

         $controls .= '<a id="page_' . $i . '" data-page="' . $i . '" class="num" style="background:' . $background . ' " href="' . $_SERVER['PHP_SELF'] . '?pn=' . $i . '"> ' . $i . '</a>';
    }

     if ($pn != $startPage) {

           $controls .= '<a href="' . $_SERVER['PHP_SELF'] . '?pn=' . ($pn - 1) . '"> prev </a>';
     }

      $controls .= "PAGE " . $pn . " of " . $lastPage ;


      $limit = "LIMIT " . ($pn-1) * $perPage . ', ' . $perPage;

      $query2 = $dbh->prepare("SELECT ContactName FROM Customers " . $limit . "");
      $query2->execute();

      $outputList = '';

      while($row = $query2->fetch(PDO::FETCH_OBJ)){ 

            $outputList .= '<h1>' . $row->ContactName . '</h1><hr />';

      } 

I would suggest you to use more easy approach. 我建议您使用更简单的方法。

Lets consider a page contains 25 results. 让我们考虑一个包含25个结果的页面。 That means: 1st Page range is: 1-25 2nd Page range is: 26-50 and so on.. 这意味着:第一页范围是:1-25第二页范围是:26-50,依此类推。

Now when a user request page 2, we should display him the results of 25-49. 现在,当用户请求第2页时,我们应该向他显示25-49的结果。 this means the results of (page-1)*25 till page*25-1 = results in 25-49. 这意味着(第1页)* 25的结果直到第* 25-1页的结果= 25-49。

Now all we need is how to tell the SQL to take those into consideration. 现在我们所需要的就是如何告诉SQL将这些考虑在内。

SELECT ContactName FROM Customers LIMIT 25 OFFSET 25;

Will produce use the desired result. 将产生使用所需的结果。

Now all you need is just pass the requested page with pn as you already did. 现在,您只需要像以前一样通过pn传递请求的页面即可。 And print the next 1-3(whatever) next\\prev pages. 并打印接下来的1-3(无论如何)下一页\\上一页。

To know how many pages there are, just do another count sql query that will give you the result and divide it by 25. 要知道有多少页,只需执行另一个count sql查询,它将为您提供结果并将其除以25。

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