javascript正则表达式对带有数字和字母的UTF8字符的支持

Question

How to generate regex for supporting utf8 characters with Numbers [0-9], letters [az] and [AZ].

I am using xregexp library to support utf-8 characters.

Till now i used :

1. XRegExp("^\\p{L}\\d{0-9}+$") //Not supporting any of them.
2. XRegExp("[^\\p{N}\\p{L}]") //Not supporting any of them.
3. XRegExp("^\\p{L}+$") // Supports only UTF-8 characters, [az] and [AZ] and not [0-9]

Thanks.

Answer 1

Just use \\\\p{L}+ in combination with [0-9] :

XRegExp("^(\\p{L}|[0-9])+$")

Note that you need to escape your backslash, there: \\\\ .

To include _/- :

XRegExp("^(\\p{L}|[0-9_/-])+$")

Note that the dash ( - ) has to be the first or last character in those brackets, due to it's special meaning.