如何在Javascript中的正则表达式中添加空格

Question

I have a string {{my name}} and i want to add white space in regular expression

var str = "{{my name}}";

var patt1 = /\{{\w{1,}\}}/gi; 

var result = str.match(patt1);

console.log(result);

But result in not match.

Any solution for this.

Answer 1

Give the word character \\w and the space character \\s inside character class [] ,

> var patt1 = /\{\{[\w\s]+\}\}/gi; 
undefined
> var result = str.match(patt1);
undefined
> console.log(result);
[ '{{my name}}' ]

The above regex is as same as /\\{\\{[\\w\\s]{1,}\\}\\}/gi

Explanation:

• \\{ - Matches a literal { symbol.

• \\{ - Matches a literal { symbol.

• [\\w\\s]+ - word character and space character are given inside Character class. It matches one or more word or space character.

• \\} - Matches a literal } symbol.

• \\} - Matches a literal } symbol.

Answer 2

Try this on

^\{\{[a-z]*\s[a-z]*\}\}$

Explanation:

• \\{ - Matches a literal { symbol.

• \\{ - Matches a literal { symbol.

• [az]* - will match zero or more characters

• \\s - will match exact one space

• \\} - Matches a literal } symbol.

• \\} - Matches a literal } symbol.

If you want compulsory character then use + instead of *.

Answer 3

To match this pattern, use this simple regex:

{{[^}]+}}

The demo shows you what the pattern matches and doesn't match.

In JS:

match = subject.match(/{{[^}]+}}/);

To do a replacement around the pattern, use this:

result = subject.replace(/{{[^}]+}}/g, "Something$0Something_else");

Explanation

• {{ matches your two opening braces
• [^}]+ matches one or more chars that are not a closing brace
• }} matches your two closing braces