mysql查询中合适的where子句

Question

Background

A table with the following columns and data such as:

---------------------------------------------------------------------------------
| Address | AddressLine2 | AddressLine3 | Locality | District | State | Country |
---------------------------------------------------------------------------------
|Sector-12|              |              |          | Faridabad| Har   | IN      |
| 311     |              |              |  Sector 3| Faridabad| Har   | IN      |
|Sector-1,|              |              |          | Faridabad| Har   | IN      |
|Plot 31  |              |              | Old Fari | Faridabad| Har   | IN      |
|         |              |              |dabad     |          |       |         |
---------------------------------------------------------------------------------

What I am trying to depict here is that the data in Address, AddressLine2, AddressLine 3, Locality can be absolutely random.

Requirement

Detect current location and find nearby schools in the database with above columns in the school table.

Process

Nearby schools are located using the Google API which returns the names of the schools along with their address.

Eg returned data:

Name: St. Albans School
Address: Sector 1, Old Faridabad, Faridabad, Har, IN

Expected result: School with Address Sector-1 and Locality as Old Faridabad

---

District, State and Country are automatically taken using the current location.

In order to process the rest of the address what is currently taking place is the school address exploded based on , and a mysql query is produced which uses IN .

Example query:

 Select * from Schools where Address IN ('Sector-1', 'Sector 1', Sector- 1'. 'Old Faridabad', ...) 

However a problem with IN query is: - If the address column contains a string such as "Sector-1," , the match with fail.

Another approach:

 Select * from Schools where Address REGEX "Sector-1|Sector 1|Sector- 1|Old Faridabad|..." 

Problem with this approach, if a school address is like: 314, Sector 19, Faridabad. Splitting the string based on , results in a search criteria of 314 in the query. Hence a school with address: 314, Sector 31, Faridabad will also result in a match though these schools are far away from each other.

Any suggestions on how to write a mysql query which helps in selecting the correct schools.

NOTE: Address can also contain text like: "314, Sector 19" together.

Answer 1

听起来您只需要检查开头和结尾的逗号即可：

REGEX "(^|, )(Sector-1|Sector 1|Sector- 1|Old Faridabad|...)(,|$)"