对于每个/查询未给出正确的值

Question

I have a table in my database. I want to get ltotal value from leave table, and then count all of ltotal . Here are my query and code I use:

$annual_query = pg_query("select ltotal from leave where lapplicant='adam' and ltype=2");

            $annual_result = pg_fetch_array($annual_query);

            if (pg_num_rows($annual_query) > 0) {

                foreach ($annual_result as $data) {

                    $total_annual = $total_annual + $data;

                }

                print($total_annual);
            }

There are 3 records in the table leave where lapplicant='adam' and ltype=2 .

Each ltotal is 1.

When I tried to run print($total_annual) the result is 2 (it must be 3).

Then I tried to print_r($annual_result['ltotal'] ), the results is just 1 (it must be 1,1,1).

Can anyone help me? Thank you.

Answer 1

Tamil pointed out the immediate problem. However - why don't you just do this in SQL?

select sum(ltotal)
from leave 
where lapplicant='adam' and ltype=2

Answer 2

pg_fetch_array() returns just one row with numeric and associative keys (same value twice when traversed). You should use pg_fetch_all() and traverse or use while loop on consecutive rows.

$total_annual = 0;
$annual_query = pg_query("select ltotal from leave where lapplicant='adam' and ltype=2");
while ($row = pg_fetch_array($annual_query)) {
    $total_annual = $total_annual + $row['ltotal'];
}
print($total_annual);

or

$total_annual = 0;
$annual_query = pg_query("select ltotal from leave where lapplicant='adam' and ltype=2");
$annual_result = pg_fetch_all($annual_query);
foreach ($annual_result as $row) {
    $total_annual = $total_annual + $row['ltotal'];
}
print($total_annual);