需要一个正则表达式来提取子字符串

Question

I am struggling to figure out a decent way to extract a substring from the below string.

Inputs: 

Invoice 1800000173 of 06/18/2014/150 USD Discnt to 07/02/2014

Invoice 1200000000 of 02.04.2014/150 Details

The above are the 2 possible combinations.

Expected Output:

Invoice 1800000173 of 06/18/2014

Invoice 1200000000 of 02.04.2014

There is a similar question asked here - Regex to get date from string but that didn't help me here. Any suggestions ?

Answer 1

"Invoice (\d+) of (\d\d[./]\d\d[./]\d{4})"

Two capturing groups, first of one or more digit for invoice number, second for the date portion. Escaping the backslashes will also need to be done appropriately.

Answer 2

Try this

([0-9]+) of ([0-9]{1,2}[,/][0-9]{1,2}[,/][0-9]{1,4})

first group contains invoice number and second date.

Answer 3

您可以尝试以下方法：

Invoice [0-9]+ of ([0-9]{2}[\/.][0-9]{2}[\/.][0-9]{4})

Answer 4

Regx for your need will be as,

Invoice\\s\\d+\\sof\\s\\d+[/.]\\d+[/.]+\\d+

And use pattern matcher to get the required sub string.. As,

public class StringProcesing {

    public void fetchSubString() {
        String s1 = "Invoice 1800000173 of 06/18/2014/150 USD Discnt to 07/02/2014";
        String s2 = "Invoice 1200000000 of 02.04.2014/150 Details";

        Pattern p = Pattern
                .compile("Invoice\\s\\d+\\sof\\s\\d+[/.]\\d+[/.]+\\d+");
        Matcher matchS1 = p.matcher(s1);
        while(matchS1.find()) {
            System.out.println(matchS1.group());
        }
        Matcher matchS2 = p.matcher(s2);
        while(matchS2.find()) {
            System.out.println(matchS2.group());
        }
    }

    public static void main(String[] args) {
        StringProcesing obj = new StringProcesing();
        obj.fetchSubString();
    }
}

Output:

Invoice 1800000173 of 06/18/2014
Invoice 1200000000 of 02.04.2014

Answer 5

You can use String#replaceFirst to capture what you want and discard rest:

String str = "Invoice 1800000173 of 06/18/2014/150 USD Discnt to 07/02/2014";
String m = str.replaceFirst("^.*(Invoice +\\d+ +of +\\d{2}[./]\\d{2}[./]\\d{4}).*$", "$1");
//=> Invoice 1800000173 of 06/18/2014

str = "Invoice 1200000000 of 02.04.2014/150 Details";
m = str.replaceFirst("^.*(Invoice +\\d+ +of +\\d{2}[./]\\d{2}[./]\\d{4}).*$", "$1");
//=> Invoice 1200000000 of 02.04.2014

Answer 6

I have nice solution :

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class RegexFun {
    public static void main(String[] args) {
        String input = "Inputs: \r\n" + "\r\n" + "Invoice 1800000173 of 06/18/2014/150 USD Discnt to 07/02/2014\r\n"
                + "\r\n" + "Invoice 1200000000 of 02.04.2014/150 Details";
        Pattern emailPattern = Pattern.compile("^Invoice \\d{10} of \\d{1,2}[ ._/-]\\d{1,2}[ ._/-]\\d{2,4}",
                Pattern.MULTILINE);
        Matcher matcher = emailPattern.matcher(input);
        while (matcher.find()) {
            String group = matcher.group();
            System.out.println("group=" + group);
        }
    }
}

By enabling MULTILINE mode you can use caret ^ to match start of each line.

Character set [ ._/-] allows you to match any date separator.