[英]Dynamicaly add methods from outside the class with a decorator
Two things I'm having trouble with. 我遇到麻烦的两件事。 Adding a method from outside that references self.
从外部添加引用self的方法。 ie
即
class A(object):
def __init__(self, name):
self.name=name
def my_name_is(self):
print("my name is %s" %(self.name))
setattr(A, my_name_is.__name__, classmethod(my_name_is))
a = A('bob')
a.my_name_is()
Because it tries to reference the name attr of 'A' rather than 'a'. 因为它试图引用'A'的名称attr而不是'a'。
The other one is adding the function with a decorator ie something like a 另一个是使用装饰器添加函数,例如a
@addMethod(A)
def say_hello_to(x):
print("hello %s" %x)
rather some kind of equivalent to 相当于某种等价物
def addMethod(cls, f)
setattr(cls, f.__name__, classmethod(f))
Question 1 : what you're looking for is a method, not classmethod
. 问题1 :您正在寻找的是一种方法,而不是
classmethod
。 In this case, a simple assignment would work: 在这种情况下,一个简单的赋值可以工作:
A.my_name_is = my_name_is
Question 2 : the expression following the @
should return a callable, ie addMethod(A)
should be a callable. 问题2 :
@
下面的表达式应返回一个可调用的,即addMethod(A)
应该是可调用的。 This can be done like this: 这可以这样做:
def addMethod(cls):
def method_assigner(f):
setattr(cls, f.__name__, f)
return f
return method_assigner
Then this works: 然后这工作:
@addMethod(A)
def say_hello_to(x):
print("hello %s" %x)
(In this example, x
will get the value of self
when say_hello_to
is called. I'm not sure I understand exactly the role of x
in your cas, but hopefully this makes it clear how to achieve what you want. Perhaps you want def say_hello_to(self, x):...
?). (在这个例子中,当
say_hello_to
时, x
将获得self
的值。我不确定我是否完全理解x
在你的cas中的作用,但希望这能清楚地表明如何实现你想要的。也许你想要def say_hello_to(self, x):...
?)。
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