[英]When referring to a JSONObject in javascript, how do I refer to it using a variable (rather than the name itself)?
I looked up all the other StackOverflow posts for this, but none seemed to work. 我为此查找了所有其他StackOverflow帖子,但似乎都没有用。 I'll post my code below:
我将在下面发布我的代码:
$.getJSON('bugs.json', function (data) {
for ( var observer = 1; observer <= data.numObservers; observer++) {
var observerName = "num" + observer;
var specs = ['congestion', 'bloodflow'];
for ( var spec in specs) {
var tableCode = "<br><table id=\"" + observer + specs[spec] + "\" > <thead> <tr> <th>" + specs[spec] + "</th> <th id=\"value\">Value</th> <th id=\"time\">Time</th></tr>";
$('body').append(tableCode);
var observerObj = data[observerName] + " kaka " + data.num1.congestion.values[1];
var selectedSpec = specs[spec];
for (var i = 0; i < observerObj[selectedSpec].values.length; i++) {
tr = $('<tr/>');
tr.append ("<td> Name </td>");
tr.append("<td>" + data[observerName][spec].values[i] + "</td>");
tr.append("<td>" + data[observerName][spec].times[i] + "</td>");
$('#'+observer+spec).append(tr);
}
}
}
});
When using the browser console log, I get an error that observerObj[selectedSpec]
doesn't work. 使用浏览器控制台日志时,出现一个错误,指示
observerObj[selectedSpec]
不起作用。
Thanks in advance for your help. 在此先感谢您的帮助。
Edit : the exact console error is: 编辑 :确切的控制台错误是:
TypeError: observerObj[selectedSpec] is undefined
var observerObj = data[observerName] + " kaka " + data.num1.congestion.values[1];
If I am reading this correctly, observerObj is a string - not an array or object. 如果我正确地阅读了此内容,则observerObj是一个字符串,而不是数组或对象。 So observerObj[selectedSpec] would not exist.
因此,observerObj [selectedSpec]将不存在。
You're trying to iterate over an array as an object. 您试图将数组作为对象进行迭代。
var specs = ['congestion', 'bloodflow'];
for ( var spec in specs) {
This is trying to iterate for every property
on specs
not each object inside of it. 这试图遍历
specs
每个property
,而不是其中的每个对象。 You want to do something like this... 你想做这样的事情...
var specs = ['congestion', 'bloodflow'];
for ( var i = 0; i < specs.length; i++) {
Then access each item via specs[i]
然后通过
specs[i]
访问每个项目
Hope this helps! 希望这可以帮助!
MDN Article about for ... in
should help too. 关于
for ... in
MDN文章也应该有所帮助。
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