在SQL Server 2008中获取日期

Question

How to split date in select query of SQL Server 2008 ? If you feed you feed current date in database and the type of that column in database is date time then It will store the date as well as time.If any one want to fetch only the date part from that column then what can he do.

I can use this query but it should not work.

SELECT DonorName, DATE(DateOfDonation) AS DateOfDonation 
FROM CreateDonorDetail;

it give error-

'DATE' is not a recognized built-in function name.

Answer 1

SQL Server 2008 has a DATE datatype - but it's disabled if your database was upgraded from a SQL Server 2005, and you didn't change the database compatibility level .

Check your compatibility level like this:

SELECT name, compatibility_level
FROM sys.databases
WHERE name = '-Your-database-name-here-'

If this compatibility level is 90 , it's set to SQL Server 2005 and you won't be able to use DATE . Update your compatibility level to 100:

ALTER DATABASE AdventureWorks2012
SET COMPATIBILITY_LEVEL = 100

Now you should be able to use DATE :

SELECT 
    DonorName, 
    CAST(DateOfDonation AS DATE) AS DateOfDonation 
FROM CreateDonorDetail;

Answer 2

Cast as Date type:

SELECT DonorName, Cast(DateOfDonation as Date) AS DateOfDonation 
FROM CreateDonorDetail;

Answer 3

在SQL Server 2008之前，您可能会使用类似以下的内容：

SELECT DonorName, CAST(FLOOR(CAST(DateOfDonation AS FLOAT)) AS datetime) AS DateOfDonation   FROM CreateDonorDetail

Answer 4

DECLARE @DateTime DATETIME

SELECT @DateTime = '2010/05/20 11:21:13'

SELECT CONVERT(VARCHAR(10),@DateTime ,105) AS Date

the result will be in dd-mm-yyyy format (105)

• Hope it will helps

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