[英]Query One to Many Relationship SQLAlchemy
I am trying to query the users based upon their skills from these tables.我正在尝试根据用户从这些表中的技能来查询他们。
class User(UserMixin, db.Model):
__tablename__ = 'users'
id = db.Column(db.Integer, primary_key=True)
email = db.Column(db.String(64), unique=True, index=True)
username = db.Column(db.String(64), unique=True, index=True)
skills = db.relationship('Skill', backref='author', lazy='dynamic')
class Skill(db.Model):
__tablename__ = 'skills'
id = db.Column(db.Integer, primary_key=True)
skill = db.Column(db.String(64), index=True)
author_id = db.Column(db.Integer, db.ForeignKey('users.id'))
i tried this in User table and got this error.我在用户表中尝试了这个并得到了这个错误。
@classmethod
def users_by_skill(cls, skill):
return User.query.join(Skill).filter(skill.skill).all()
AttributeError: 'str' object has no attribute 'skill'
Where i am missing badly?我在哪里严重失踪?
You define the following class method:您定义以下类方法:
@classmethod
def users_by_skill(cls, skill):
return User.query.join(Skill).filter(skill.skill).all()
You are probably expecting to use this function like so:您可能希望像这样使用这个函数:
users = Users.users_by_skill('nunchuk')
That means the skill
argument in users_by_skill
is a string.这意味着
users_by_skill
的skill
参数是一个字符串。 Then, you try to use skill.skill
, which essentially is like doing 'nunchuk'.skill
.然后,您尝试使用
skill.skill
,这本质上就像在做'nunchuk'.skill
。 Python does not have a skill
attribute on the string class, hence the error. Python 在字符串类上没有
skill
属性,因此出现错误。
The filter
function actually takes a Criteria
object. filter
函数实际上接受一个Criteria
对象。 In other words, you don't pass it a value like "filter"
, you instead pass it a criterion that represents the notion of "the skill column on the Skill table must equal 'nunchuk'".换句话说,您没有向它传递像
"filter"
这样的值,而是向它传递一个标准,该标准表示“技能表上的技能列必须等于 'nunchuk'”的概念。 You can do this using syntax like the following:您可以使用如下语法执行此操作:
@classmethod
def users_by_skill(cls, skill_name):
return User.query.join(Skill).filter(Skill.skill == skill_name).all()
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