php preg_replace帮助，请删除所有包含多个单词和单个字符的实例

Question

I have the following

$search_keywords = preg_replace('/\s{1,}(and\s*)*/', ' ', $search_keywords);

which removes the word "and" and any extra spaces from $search_keywords

but when i try and add other words to remove like so

$search_keywords = preg_replace('/\s{1,}(and|with\s*)*/', ' ', $search_keywords);

any string with and in it it will remove the word but not the extra space, but it will remove the word "with" and the space if found in the string?

i also tried the following

$search_keywords = preg_replace('/\s{1,}(and\s*)(with\s*)*/', ' ', $search_keywords);

but that worked only for the word "and" but didn't remove the word "with" if present.

so what i am trying to do is remove all instances of the words "and" and "with" from my varible and remove any extra spaces that may leave.

Also i'd like to remove all single characters from the string which appear on their own ie: " a "," i "," £ "," ? " etc "any" single char that appears on its own (surrounded by spaces)

so lets say my string is: "do u want steak and chips with a asparagus sauce?"

I want to be able to have the following returned: "do want steak chips asparagus sauce"

therefor it has removed the words with and and as well as the single char u , a and ?

hope that makes sence?

appreciate any help thanks

Answer 1

You can correct your regex using:

$search_keywords = preg_replace('/\s+(\S(\s|$)|((and|with)\s*(\S\s+)?)+)/i', ' ', $search_keywords);

Your regex (and|with\\s*) will allow 0 or more spaces after with .

Working Demo

Answer 2

尝试这个：

$search_keywords = preg_replace(array('/\s{1,}(and\s*)*/','/\s{1,}(with\s*)*/'), ' ', $search_keywords);