找到一个数组元素并将其设置为Ruby中的最后一个？

Question

In my Ruby on Rails app I have an array:

Car.color.values.map{|x| [x.text, x]}.sort 

This code gives me the following array:

[["Beżowy", "beige"], ["Biały", "white"], ["Brązowy", "brown"], ["Czarny", "black"], ["Czerwony", "red"], ["Fioletowy", "violet"], ["Grafitowy", "graphite"], ["Inny", "other"], ["Niebieski", "blue"], ["Perłowy", "pearl"], ["Srebrny", "silver"], ["Szary", "grey"], ["Zielony", "green"], ["Żółty", "yellow"]]

Now I want to find this element: ["Inny", "other"] and set it to last element of an array. How can I do this in Ruby?

Answer 1

a = [["Beżowy", "beige"], ["Biały", "white"], ["Brązowy", "brown"], ["Czarny", "black"], ["Czerwony", "red"], ["Fioletowy", "violet"], ["Grafitowy", "graphite"], ["Inny", "other"], ["Niebieski", "blue"], ["Perłowy", "pearl"], ["Srebrny", "silver"], ["Szary", "grey"], ["Zielony", "green"], ["Żółty", "yellow"]]
a.push(a.delete(["Inny", "other"]))
# => [["Beżowy", "beige"], ["Biały", "white"], ["Brązowy", "brown"], ["Czarny", "black"], ["Czerwony", "red"], ["Fioletowy", "violet"], ["Grafitowy", "graphite"], ["Niebieski", "blue"], ["Perłowy", "pearl"], ["Srebrny", "silver"], ["Szary", "grey"], ["Zielony", "green"], ["Żółty", "yellow"], ["Inny", "other"]]

Answer 2

For a more generic solution (when you don't know the exact value of the element), you can use partition , and then concatenate the answers back:

arr = [["Beżowy", "beige"], ["Biały", "white"], ["Brązowy", "brown"], ["Czarny", "black"], ["Czerwony", "red"], ["Fioletowy", "violet"], ["Grafitowy", "graphite"], ["Inny", "other"], ["Niebieski", "blue"], ["Perłowy", "pearl"], ["Srebrny", "silver"], ["Szary", "grey"], ["Zielony", "green"], ["Żółty", "yellow"]]
arr.partition { |k, v| v != "other" }.inject(:+)
# => [["Beżowy", "beige"], ["Biały", "white"], ["Brązowy", "brown"], ["Czarny", "black"], ["Czerwony", "red"], ["Fioletowy", "violet"], ["Grafitowy", "graphite"], ["Niebieski", "blue"], ["Perłowy", "pearl"], ["Srebrny", "silver"], ["Szary", "grey"], ["Zielony", "green"], ["Żółty", "yellow"], ["Inny", "other"]] 

Answer 3

Array#rassoc Searches through the array whose elements are also arrays.

arr = [["Beżowy", "beige"], ["Biały", "white"], ["Brązowy", "brown"], .....
arr.push(arr.delete(arr.rassoc("other")))

Answer 4

i = a.index(["Inny", "other"])
a.take(i) + a.drop(i + 1) << ["Inny", "other"]
=> [["Beżowy", "beige"], ["Biały", "white"], ["Brązowy", "brown"], ["Czarny", "black"], ["Czerwony", "red"], ["Fioletowy", "violet"], ["Grafitowy", "graphite"], ["Niebieski", "blue"], ["Perłowy", "pearl"], ["Srebrny", "silver"], ["Szary", "grey"], ["Zielony", "green"], ["Żółty", "yellow"], ["Inny", "other"]]