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有什么办法可以缩短这个时间吗

[英]IS there any way i can make this shorter

I am learning how to use untiy in my spare time by reading a beginners book and looking up stuff online in the book there is a exercise that asks me 通过阅读初学者的书并在线查找书中的内容,我正在学习如何在业余时间使用不整洁,有一个练习要求我

to create a script that outputs the numbers from 1 to 10 in to the console but dose not output any multiple of 3 and 5 instead outputting the phrase "programming is awesome " 创建一个脚本,将数字从1到10输出到控制台,但不输出3和5的倍数,而是输出短语“ programming is awesome”

while i have achieved this task by using this code 虽然我通过使用此代码实现了此任务

using UnityEngine;
using System.Collections;

public class Loops : MonoBehaviour {

// Use this for initialization
void Start () {

    for(int i = 1; i <= 10; i++)
    {
        if(i == 3 )
            print ("Programming is Awesome!");
        else if (i == 5)
            print ("Programming is Awesome!");
        else if (i == 6)
            print ("Programming is Awesome!");
        else if (i == 9)
            print ("Programming is Awesome!");
        else if (i == 10)
            print ("Programming is Awesome!");
        else
            print (i);
    }
}


}   

i was wondering if there was any way to achieve the same result only by using less lines of code 我想知道是否只有通过使用较少的代码行就能达到相同的结果

You want to use the modulus (aka modulo) operator (%) for this task. 您要使用模数(aka模)运算符(%)来完成此任务。 It returns the remainder of a division, so when the result of a modulus operation is 0 you know you have a multiple of the divisor. 它返回除法的余数,因此,当模运算的结果为0时,您就知道除数是倍数。

for (int i = 1; i <= 10; i++)
{
    if(i % 3 == 0 || i % 5 == 0)
        print("programming is awesome");
    else
        print(i);
}

The point of this exercise is that you should calculate the multiples, not just make one condition for every value that you know is a multiple. 本练习的重点是您应该计算倍数,而不仅仅是为您知道是倍数的每个值都设定一个条件。

Use the modulo operator to check it a number is an even multiple of another. 使用模运算符检查它是否为另一个的偶数倍。 This shows what the modulo operator returns for some values: 这显示了模运算符对于某些值返回的内容:

 i    i % 3
------------
 1      1
 2      2
 3      0
 4      1
 5      2
 6      0
 7      1

As you see, i % 3 evaluates to 0 when i is a multiple of three. 如您所见,当i为3的倍数时, i % 3值为0 You can use that to check if the number is a multiple of three: 您可以使用它来检查数字是否为三的倍数:

if (i % 3 == 0) {
  print ("Programming is Awesome!");
}

Now you should be able to do the same for five also, and incorporate it in your code. 现在,您应该也可以对五个执行相同的操作,并将其合并到您的代码中。

  for (int i = 1; i <= 10; i++)
        {
            print((i % 3 == 0 || i % 5 == 0)? "programming is awesome" : i));
        }

check out also using ternary operator. 也可以使用三元运算符进行检出。

Ways of doing this 这样做的方式

if(i == 3 || i == 5 || i == 6 || i == 9 || i == 10){
    print ("Programming is Awesome!");
}
else {
    print (i);
}

Better way By Using the modulo operator 使用取模运算符的更好方法

if( i % 3 == 0 || i % 5 == 0){
    print ("Programming is Awesome!");
}
else {
    print (i);
}

Use can also try 使用也可以尝试

print((i % 3 == 0 || i % 5 == 0)? "Programming is Awesome!" : i));

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