在Lua中处理StackOverflowException

Question

I'm making an IRC bot in C#, and want to have Lua be executable via a command. I already have this working, and have overcome some basic obstacles, but now I'm having a larger problem with a StackOverflowException; My friend gave me some Lua code to run, which every time seems to cause a StackOverflowException, no matter how hard I try to prevent it.

print(string.find(string.rep("a", 2^20), string.rep(".?", 2^20)))

So, with this being executed using LuaInterface (LuaInterface 2.0.0.16708 to be precise) - I get a StackOverflowException in my code and I don't seem to be able to fix this, looking at some previous questions.

I know parsing code before executing it to predict stack overflows is hard, so I don't know how I would circumvent this. I have already tried multi-threading (which solved a previous problem where yielding code wouldn't return control back to C#) but this does not seem to help.

Answer 1

To get around that particular error use Lua 5.2.2 or newer. The case is a reported bug that got fixed in the version 5.2.2. It gives "pattern too complex" error instead.

And as far as sandboxing is concered why not fashion it after the Lua live demo as suggested in this SO answer ? I don't know how secure it is but I'd presume the authors have both the incentive and capability of making it as secure as possible. The sources can be found from here .