如何根据另一个表中的％LIKE％值过滤表

Question

So i have tableA and tableB. A is of raw domains data, like http://www.cnn.com , where B has it trimmed up all nice and tidy, like cnn.com. I need to pull websites that aren't in tableB that are in tableA. I imagine a left join with some crazy %LIKE% operator is placed in there.

this is what i have so far but it doesn't work.

SELECT tableA.domain, sum(tableA.views) views FROM `tableA` LEFT JOIN tableB ON tableA.domain %LIKE% tableB.name WHERE tableB.name IS NULL AND GROUP BY tableA.domain ORDER BY views DESC

thank you!

Answer 1

try this

 SELECT tableA.domain, sum(tableA.views) views FROM `tableA` 
 LEFT JOIN tableB ON tableA.domain  LIKE CONCAT('%', tableB.name ,'%')
 WHERE tableB.name IS NULL 
 GROUP BY tableA.domain 
 ORDER BY views DESC

you have two errors in your try.

1- LIKE CONCAT('%', tableB.name ,'%') // you have to use CONCAT

2- remove the AND before group by

Answer 2

The % are suppose to be around the value you're comparing to, not the LIKE keyword itself.

It should be something like

SELECT column
FROM table
WHERE column LIKE '%pattern%';