如何在C / C ++中最多计算1000位数字中的位数

Question

How can I count the number of digits in a number up to 1000 digits in C or C++

#include <stdio.h>

int main()
{
    int num,counter=0;

    scanf("%d",&num);

    while(num!=0){
        num/=10;
        counter++;
    }

    printf("%d\n",counter);
}

This code works just for numbers up to 10 digits — I don't know why.

Answer 1

Since most computers can't hold an integer that is 1000 digits, you will either have to operate on the input as a string or use a Big Number library. Let's try the former.

When treating the input as a string, each digit is a character in the range of '0' to '9' , inclusive.

So, this boils down to counting characters:

std::string text;
cin >> text;
const unsigned int length = text.size();
unsigned int digit_count = 0;
for (i = 0; i < length; ++i)
{
  if (!std::isdigit(text[i]))
  {
    break;
  }
  ++digit_count;
}
cout << "text has " << digit_count << "digits\n";