直接在Parse REST API中获取查询

Question

I implemented a query for chat messages in PARSE using their REST API. My problem is, I am getting messages where somehow sender and receiver was the same.

Clearly a bug or a test in the debug version. Anyway, those messages should not get displayed.

Obviously I want to fix that by changing my PARSE Query and not go through all the messages and delete the wrong ones. Is that even possible? I am not very good with the PARSE REST API.

This is what I am passing to PARSE API:

         $aWhere = array(
                        self::FIELD_SENDER =>   array('$in' => array($sUsername1, $sUsername2)),
                        self::FIELD_RECEIVER => array('$in' => array($sUsername1, $sUsername2)),                    
                    );  

$url = 'https://api.parse.com/1/classes/test?where='.json_encode($aWhere);

url then gets passed into CURL

I want to avoid messages where self::FIELD_SENDER is $sUsername1 AND self::FIELD_RECEIVER is $sUsername1 and the same goes in respect to $sUsername2 .

Answer 1

I strongly recommend you instead fix your data using a Job.

As for what you are asking for, you can't quite get what you want. Let's explore the logic:

• You could try building an OR query
  • Query1: sender != user1 AND receiver != user1
  • Query2: sender != user2 AND receiver != user2

This may seem like it will give the results you want, except the situation excluded by Query1 is satisfied by Query2 and vice versa.

What about using $nin (not in):

• sender not in (user1, user2)
• receiver not in (user1, user2)

Unfortunately this will also exclude the following messages:

• sender=user1, receiver=(anyone)
• sender=user2, receiver=(anyone)
• sender=(anyone), receiver=user1
• sender=(anyone), receiver=user2