[英]unix ls command in java
Hi I am trying to list folders in unix "ls" command style in java. 嗨,我正在尝试在Java中以unix“ ls”命令样式列出文件夹。 I have a folder tree like this : 我有一个像这样的文件夹树:
My file structure is as follows : 我的文件结构如下:
private class Node{
public List<Node> children= new ArrayList<Node>();
public String value;
public Node(String value){
this.value = value;
}
public void addSubDirectory(Node child){
children.add(child);
}
}
Problem : I am not able to recurse more than the children of current folder when there is nothing after the ' * ' in a command 问题:当命令中的“ *”后没有任何内容时,我不能递归地超过当前文件夹的孩子
For eg. 例如。 command 命令
ls A/B/*/*/E/ and ls A/*/*/M/*/E/ works ls A / B / * / * / E /和ls A / * / * / M / * / E /
But command " ls A/ * " only shows 但是命令“ ls A / *”仅显示
BY 通过
Code to traverse 遍历代码
public void showCommand(Node root, String command){
String argument = command.substring(3);
System.out.println("command is ls "+argument);
show(root,argument);
}
private void show(Node root, String cmd){
int N = cmd.length();
if(N==0){
// case when end of command is reached
for(Node child:root.children){
System.out.println(child.value);
}
}else{
char c = cmd.charAt(0);
// case when folder name is present in command
if((c!='*') && (c!='/')){
for(Node child:root.children){
if(child.value.equals(String.valueOf(c))){
show(child,cmd.substring(1));
}
}
return;
}else if(c=='*'){
// case when * is present in command
// i think problem lies here
if(N==1){
System.out.println(root.value);
preOrderTraverse(root);
}else{
for(Node child:root.children){
show(child,cmd.substring(1));
}
}
return;
}else if(c=='/'){
// case when '/' is present in commmand
show(root,cmd.substring(1));
return;
}
}
}
When the last char in the command is a *, you call back the showCommand
method with an empty cmd and when the method receives an empty cmd string the recursion stops. 当命令中的最后一个字符为*时,您将使用空cmd调用showCommand
方法,并且当该方法接收到空cmd字符串时,递归将停止。
When the current char c
is a *, you should check it's the last char in cmd
, if it is then you should send the current cmd
instead of cmd.substring(1)
. 当当前字符c
为*时,应检查它是cmd
的最后一个字符,如果是,则应发送当前cmd
而不是cmd.substring(1)
。 That way it should go through the hierarchy recursively. 这样,它应该递归地遍历层次结构。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.