如何使PHP调试过程？

Question

I am trying to make a conditional PHP debugger tool, that, when called, will write certain steps in execution like a position in code which corresponds to a function or level.

I formed it as:

define("DEBUGGING", TRUE); //IF TRUE, TURNS ON CONDITIONAL CODE THAT RETURNS CODE FLOW

and

if (DEBUGGING) { echo "RETURN LINE OF CODE OR SOMETHING ELSE"; }

which I insert where needed.

Is there a better way to do this? I did turn all PHP warning levels ON, but that is not enough as I don't know which part of the code was executed due to redundant functions.

Thanks!

Answer 1

Instead of needlessly cluttering up your code you should just install Xdebug .

This will output full stack traces in HTML format when there is an error in your code.

Here is an output example I found via google:

Also, Xdebug provides remote debugging so that you can use a real debugger (I use PHPStorm ) to step through your code.

Answer 2

to get a stack trace easily

try{
    throw new Exception();
}catch(Exception $e ){
    echo $e->getTraceAsString();
}

This will give you a real nice stacktrace.