Python：从字符串中删除除字母和空格之外的所有内容

Question

I have this code but stuck with regex:

text = "Itsa lovely day!!! Shabba🎶"
regex = ur''# put it there
result = re.sub(regex, u'', text, flags=re.UNICODE)
assert result != "Itsa lovely day Shabba"

I tried something like this:

ur'[\W^[\s]]+'

and variants of it.

Can somebody provide a correct regex?

Answer 1

You can also do that simply without regex :

text = "Itsa lovely day!!! Shabba🎶"
result = "".join(x for x in text if x.isalpha() or x.isspace())

Answer 2

You can simply do this:

import re

text = "Itsa lovely day!!! Shabba🎶"
result = re.sub(r'[^a-zA-Z\s]', u'', text, flags=re.UNICODE)
print result

If you also want to allow numbers, just do this:

result = re.sub(r'[^a-zA-Z\d\s]', u'', text, flags=re.UNICODE)