[英]CSS: “Attribute selector” and “not()” together
I have the following rule: 我有以下规则:
a:not(.ui-spinner-button):active
{
...
}
I would like a more general rule specifying that "style must applied to all A tag that does NOT have a class name that begin with 'ui-' ". 我想要一个更通用的规则,指定“样式必须应用于所有不具有以'ui-'开头的类名的A标记”。
So, I should "merge" this kinf of definition [class*='ui-']
with not()
. 因此,我应该用
not()
“合并”定义[class*='ui-']
。
Is possible in some way? 有可能吗? Thank you.
谢谢。
Yes, it's possible, just put [class*='ui-']
inside a not()
. 是的,有可能,只需将
[class*='ui-']
放入not()
。
a {
color: cyan;
}
a:not([class*='ui-']) {
color: pink;
}
<a class='ui-foobar'>ui-foobar</a>
<a class='foobar'>definitely not ui-foobar</a>
The first link will be cyan, the second one pink. 第一个链接为青色,第二个链接为粉红色。
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