将URL参数传递给Python

Question

I have the following code in one of my templates. 我的模板之一中包含以下代码。

<html>
<body>
    <script>
        var val1 = 10;
        var val2 = 20;
    </script>
    <a href="/generate/">Generate</a>
</body>
</html>

I wish to use the values val1 and val2 in the generate function in the views.py file. 我希望在views.py文件的generate函数中使用值val1和val2。 It would be something like this. 就像这样。

def generate(request):
    # do something with val1 and val2

I am lost as to how I can pass these values to the function. 我不知道如何将这些值传递给函数。 What is the best practice for this, should I try to retrieve the information through URL parameters? 最佳做法是什么，我应该尝试通过URL参数检索信息吗？ Or perhaps I should just remove the Javascript and do everything in Python directly in the generate() function? 或者，也许我应该删除Javascript，然后直接在generate()函数中使用Python做所有事情？

Thank you for your help! 谢谢您的帮助！

Answer 1

You need to apply HTTP methods such as GET or POST. 您需要应用HTTP方法，例如GET或POST。

use this code in view template (example - index.html ): 在视图模板中使用以下代码（示例index.html ）：

<html>
<body>
    <form method="post" action="/generate">
        {% csrf_token %}
        <input type="number" name="val1" value="10">
        <input type="number" name="val2" value="20">
        <input type="submit" value="generate">
    </form>
</body>
</html>

and use this code in views.py : 并在views.py使用此代码：

def index(request):
    return render_to_response('index.html', RequestContext(request))

def generate(request):
    val1 = request.POST.get('val1', 0)
    val2 = request.POST.get('val2', 0)
    sum = val1 + val2

    return HttpResponse(str(sum))

This link is helpful for you: https://docs.djangoproject.com/en/dev/topics/forms/ 该链接对您有所帮助： https : //docs.djangoproject.com/en/dev/topics/forms/

Answer 2

Pass the parameters using GET: 使用GET传递参数：

<html>
    <body>
        <a href="/generate/?val1=10&val2=20">Generate</a>
    </body>
</html>

Now you can access them in view using request attribute: 现在，您可以使用request属性在视图中访问它们：

def generate(request):
    if request.method == 'GET':
        val1 = request.GET.get('val1')
        val2 = request.GET.get('val2')
        #futher code

https://docs.djangoproject.com/en/dev/ref/request-response/# https://docs.djangoproject.com/en/dev/ref/request-response/#

将URL参数传递给Python

问题描述

2 个解决方案

解决方案1
3 2014-07-07 09:22:25

解决方案2
2 已采纳 2014-07-07 09:31:36

将URL参数传递给Python

问题描述

2 个解决方案

解决方案1 3 2014-07-07 09:22:25

解决方案2 2 已采纳 2014-07-07 09:31:36

解决方案1
3 2014-07-07 09:22:25

解决方案2
2 已采纳 2014-07-07 09:31:36