将N位数字的连续行读入整数数组，每个数字位于单个数组位置

Question

My file has a 9 digit number in each line and I want to extract each number line-wise and try storing it in a integer array with each digit in each array position.

I tried,

while((fgets ( sequence, 9, loose ) != NULL)) {
    if((sequence[0]-'0')==1)
        count(sequence[1]-'0');
    else
        break;
}

copying each line to a array called sequence and then converting it to number by sequence[0]-'0' , but it doesn't seem to work right; it returns some random number value and loses the file descriptor of my required file.

My file looks something like this 123456789 123456798 123456879 123456897 123456978

i just want first line to be stored as sequence[0]=1,sequence[1]=2,... then the next line text to be over written on sequence[] and so on until end of file

Answer 1

If I understand your problem correctly, I'd suggest that you accept each line of input as a string to a two dimensional character array. That way you get each number in its own row with each of the digits in the columns. I can give you the code if you need, but this is pretty straightforward.

Note - You can convert the characters back to integers for further manipulation

EDIT - Added code

with open('/root/text.txt') as f:
    number = f.readlines()
number = [x.strip('\n') for x in number]
print number

The number printed is a list.

number[0] will give you the first number in your file (123456789)

number[0][0] will give you 1.

int(number[0]) can give you the integer 123456...as opposed to the corresponding string.

Edit 2 - oops. Just realized I gave you python code :-\\