[英]How to send more than one AJAX request to one PHP file?
I am trying to send multiple AJAX requests to one PHP file, because I am creating a big project and in the index page there is a lot of buttons which have different functionality. 我试图将多个AJAX请求发送到一个PHP文件,因为我正在创建一个大项目,并且在索引页面中有许多具有不同功能的按钮。
It would be very bad to make for each button a file with PHP. 使用PHP为每个按钮创建一个文件将是非常糟糕的。
This is my AJAX code: 这是我的AJAX代码:
$('#check').click(function(){
var val = $(this).filter('input:checked').val();
$.ajax({
url: './process/upload.php',
type: 'POST',
data: {'check': val},
success: function(data){
alert(data);
}
});
});
In the PHP file I can't add if(isset($_POST['check'])){}
It won't work but if I write it like this if(isset($_POST)){}
在PHP文件中,我无法添加
if(isset($_POST['check'])){}
,但是如果我这样写它, if(isset($_POST)){}
To do it like if(isset($_POST)){}
it will cause some errors if I add if(isset($_POST)){}
for another button 像
if(isset($_POST)){}
做,如果我为另一个按钮添加if(isset($_POST)){}
,则会导致一些错误
This is the HTML: 这是HTML:
<input type="checkbox" name="check" class="check" id="check" checked>
Why not include a "source" parameter? 为什么不包括“源”参数? eg
例如
data: {check: val, source: 'from_button_A' }
and then you check if($_POST['source'] == 'from_button_A')
and go from there. 然后检查
if($_POST['source'] == 'from_button_A')
并从那里继续。
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