将指向char数组的指针初始化为可变的最佳方法是什么？

Question

It is clear that initializing a char array like

char* string = "foobar";

will make it immutable. On the other hand, initializing a char array like

char string[] = "foobar";

will be make it mutable.

What is the best way to make a mutable initialization of pointer to a char array?

// member char arrays are immutable
char* arr[] = {"foo", "bar"};

Answer 1

假设您拥有C99功能，复合文字可以解决这个问题：

char *arr[] = { (char[]){"foo"}, (char[]){"bar"} };

Answer 2

One options is to guess the maximum size of the strings in the array, and use:

char arr[][SIZE] = {"foo", "bar"};

where SIZE is to be replaced by a number.

char arr[][4] = {"foo", "bar"};

would work given the strings but it won't if you use:

char arr[][4] = {"foo", "fubar"};

When such a line is compiled, gcc prints the following warning:

warning: initializer-string for array of chars is too long [enabled by default] char arr[][4] = {"foo", "fubar"};

If you are using a different compiler, it might not complain. Just be aware.