如何从左至右打印输出？

Question

Below codes run perfectly fine. But how to I print converted number in left to right manner. For example if I input 898989, it will give me the output DB7AD. How do I print

• DB7AD to

   DB 7 A D 

  Codes:

   public static void Main() { int decimalNumber, quotient; int i = 1, j, num = 0; char [] hexadecimalNumber = new char[100]; char temp; Console.WriteLine("Decimal to HexaDecimal conversion using Ascii code.\\n"); Console.WriteLine("Input DECIMAL NUMBER(S) you want to convert to HEXADECIMAL(S):\\t\\n"); Console.Write("Decimal Numbers : \\t"); decimalNumber = int.Parse(Console.ReadLine()); quotient = decimalNumber; while (quotient != 0) { num = quotient % 16; if (num < 10) num = num + 48; else num = num + 55; temp = Convert.ToChar(num); hexadecimalNumber[i++] = temp; quotient = quotient / 16; } Console.Write("HexaDecimal Numbers : \\t"); for (j = i - 1; j > 0; j--) Console.Write(hexadecimalNumber[j]); Console.WriteLine(); Console.Read(); } 

Answer 1

Since you are printing your number character-by-character, you need to modify this loop

for (j = i - 1; j > 0; j--) {
    Console.Write(hexadecimalNumber[j]);
}

in such a way as to print zero tabs before the first digit, one tab before the second digit, two tabs before the third digit, and so on. You can do it by making a string tabs variable, and adding a "\\t" to it after each iteration:

string tabs = "";
for (j = i - 1; j > 0; j--) {
    Console.WriteLine(tabs + hexadecimalNumber[j]);
    tabs += "\t";
}

Demo on ideone.